Answer to Question #142907 in Electricity and Magnetism for sridhar

Question

Two similar coils which are separated by 2m are having radius of 1m and 80 turns have a common axis.Calculate the strength of magnetic field at a point midway between them on their common axis when a current is 0.2A .
Ans 0.04√2T

Answer 1

The magnetic field along the axis of a ring z=1 m away from its center produced by a single coil is

$$b=\frac{\mu_0}{2}\frac{NIr^2}{(z^2+r^2)^{\frac{3}{2}}}.$$

For two coils, it will be

$$B=\mu_0\frac{NIr^2}{(z^2+r^2)^{\frac{3}{2}}}=7.109\space\mu\text{T}.$$