Question #142976

The equation for an alternating current is given by i - 77 sin 314 t. Find the peak value, frequency, time period and instantaneous value at t-2 ms

Expert's answer

Let us write the equation for alternating current in general form

i(t)=Im⋅Sin(2πf⋅t)i(t)=I_m \cdot Sin{(2 \pi f \cdot t)}

Then

Peak current Im=77AI_m=77A

Frequency f=3142π=3142⋅3.14=501sf=\frac{314}{2\pi}=\frac{314}{2\cdot 3.14}=50 \frac{1}{s}

Time period T=1f=150=0.02sT=\frac{1}{f}=\frac{1}{50}=0.02s

Instantaneous value at t=2 ms.

i(0.002)=77⋅Sin(314⋅0.002)=45.24Ai(0.002)=77 \cdot Sin{(314 \cdot 0.002)}=45.24A


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