In eq. E=1/(4πε_o )∫ρ_v R" " /R^3 dv' , let ρ_v to be known. Explain in detail how you would numerically evaluate the vector integral to obtain E.
As per the question,
E=1(4πεo)∫ρvRR3dvE=\frac{1}{(4πε_o )}\int \frac{\rho_v R}{R^3}dvE=(4πεo)1∫R3ρvRdv
=14πϵo∫ρvR4πdv4πR3=\frac{1}{4\pi \epsilon_o}\int \frac{\rho_v R 4\pi dv}{4\pi R^3}=4πϵo1∫4πR3ρvR4πdv
=14πϵo∫ρvR4πdvv=\frac{1}{4\pi \epsilon_o}\int \frac{\rho_v R 4\pi dv}{v}=4πϵo1∫vρvR4πdv
=ρoR×4π4πϵoln(v)+c=\frac{\rho_o R\times 4 \pi}{4\pi \epsilon_o} \ln(v)+c=4πϵoρoR×4πln(v)+c
=ρoRϵoln(v)+c=\frac{\rho_o R}{\epsilon_o}\ln (v)+c=ϵoρoRln(v)+c
Hence, the required electric field will be calculated from the above.
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