Question #128308

A hollow rectangular waveguide has dimensions a = 2.28 cm., b = 1.01 cm. What TE modes will propagate in this waveguide if the frequency of the electromagnetic waves is 1.7 x 1010 Hz? What range of frequencies can be used to excite only one TE mode?


1
Expert's answer
2020-08-04T16:01:13-0400

As per the given question,

Dimensions of the wave guide a=2.28cm,b=1.01cma = 2.28 cm, b = 1.01 cm

Frequency of the electromagnetic wave (f)=1.7×1010Hz(f)=1.7\times 10^{10}Hz

Range of frequencies =?

Cut off wave guide for the dominant TE10TE_{10} mode =2(ma)2+(nb)2=\frac{2}{\sqrt{(\frac{m}{a})^2+(\frac{n}{b})^2}}

=2(12.28)2+(01.01)2=\frac{2}{\sqrt{(\frac{1}{2.28})^2+(\frac{0}{1.01})^2}}

=0.046cm=0.046 cm

For the higher wavelength =2(ma)2+(nb)2=\frac{2}{\sqrt{(\frac{m}{a})^2+(\frac{n}{b})^2}}

=2(12.28)2+(11.01)2=\frac{2}{\sqrt{(\frac{1}{2.28})^2+(\frac{1}{1.01})^2}}

=4.02cm=4.02 cm

Hence the required frequencies

fc=c2a=3×1082×2.28×102Hzf_c =\frac{c}{2a} =\frac{3\times 10^8}{2\times 2.28 \times 10^{-2}}Hz

=0.657×1010Hz=0.657 \times 10^{10}Hz

and

fc=c2bf_c=\frac{c}{2b}


=3×1082×1.10×102Hz=\frac{3\times 10^8}{2\times 1.10 \times 10^{-2}}Hz


=1.36×1010Hz=1.36\times 10^{10}Hz



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