A point charge of +10-7C is situated at the centre of a cube of side 1 m. Calculate the electric flux through the surface of the cube
Given that;
q=10−7Cq=10^{-7}Cq=10−7C
Electric flux is;
ϕ=qϵ0\phi=\frac{q}{\epsilon_0}ϕ=ϵ0q
ϕ=10−78.85×10−12\phi= \frac{10^{-7}} {8.85\times10^{-12}}ϕ=8.85×10−1210−7
ϕ=0.1129×105\phi=0.1129\times10^5ϕ=0.1129×105
ϕ=1.13×104Nm2/C\phi=1.13\times10^4 Nm^2/Cϕ=1.13×104Nm2/C
Therefore the electric flux is 1.13×104Nm2/C1.13\times10^4 Nm^2/C1.13×104Nm2/C
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments