1.) In case of DC circuit, inductor acts a straight wire after a long time and acts as a wire of infinite resistance at t=0
so, we have to find the final current so at that time inductor will act as a wire of negligible resistance
Hence, final current= V/R=2/5 Amperes =0.4 A
2.) Expression for the Current in an LR Series Circuit, "I(t)" "= \\dfrac{V}{R}(1-e^{-Rt\/L})"
rate of change of current with time="\\dfrac{V}{L}(e^{-Rt\/L})"
at t=0, Rate of change of current = 1 A/s
3.) From Kirchhoff's voltage law
"V_s=IR+L \\dfrac{dI}{dt}"
"2=2*5+2*\\dfrac{dI}{dt}"
"\\dfrac{dI}{dt}=-4"
here negative sign shows that there is decrease in current
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