Question

a solenoid having an air core and 10 cm long has 100 turns and its area of cross-section is 5 cm² . find co-efficient of self-inductance of the solenoid?
Please ans this broadly thanks

Answer 1

$L=\mu$ $N^2\Alpha/l$ ................(1)

where L is the co-efficient of self-inductance of the solenoid

$\mu=4\pi*10^{-7}$

N being the number of turns

A is the area of cross-section of the solenoid

l is the length of the solenoid

after substituting the values in the equation (1)

$L$ $=$ $1*4\pi*10^{-7}*(100*100)*5*10^{-4}/0.1$

$L=62.8*10^{-8} henry$