The circuit diagram has the following outline:
Here we have: R1=1Ω , R2=2Ω , E=1.5V, r=1Ω
1) the combined external resistance is
R=R1+2R2=1+1=2Ω
2) the current in the circuit is
I=4r+R4E=4+24⋅1.5=1A
3) the lost volts in the battery are
U=4Ir=4⋅1⋅1=4V
4) the current through R2 is
I2=2I=0.5A
Comments
wow nice solution
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