Question #92880

A balanced delta connected load takes 20 KVA at 0.8 power factor when connected to a 415 v, 3 sigma system.Calculate the resistance of each branch of balanced star connected non reactive load which when connected to same supply coil takes the same power?

Expert's answer

The active power per each phase (since the load is balanced, it means that all branches have the same impedance) can be calculated as


P=S cosϕ3.P=\frac{S\space\text{cos}\phi}{\sqrt{3}}.

With non-reactive load each phase of the star-connected load has power of


P=Uphase2Rbranch,P=\frac{U^2_\text{phase}}{R_\text{branch}},

and therefore


Rbranch=Uphase2P=3Uphase2S cosϕ=3[Uline2/3]S cosϕ,R_\text{branch}=\frac{U^2_\text{phase}}{P}=\frac{\sqrt{3}\cdot U^2_\text{phase}}{S\space\text{cos}\phi}=\frac{\sqrt{3}\cdot [U^2_\text{line}/3]}{S\space\text{cos}\phi},

Rbranch=34152/3200000.8=6.21 Ω.R_\text{branch}=\frac{\sqrt{3}\cdot 415^2/3}{20000\cdot0.8}=6.21\space\Omega.


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