Given:
N=50; A=10cm2=10−3m2; B=0.75T; t=0.2s;
α=1800;
Solution:
Formula of induced EMF:
E=−NΔtΔϕ; Let's find Δϕ - magnetic flux though the coil;
Δϕ==∫0αBδ(Acosα)=∫0πBδ(Acosα)=−2BA; here B and A constant;
E=−NΔtΔϕ=Nt2BA=50×0.2s2×10−3m2×0.75T=0.375V;
Answer:
E=0.375V.
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