Answer to Question #350600 in Electric Circuits for Tobi

Question #350600

a coil with 50 turns and area 10cm2 is oriented with a plane perpendicular with a 0.75-T magnetic field. if the coil is rotated over(rotated through 180) in 0.20s. what is the average emf induced in it. 0.375v

1
Expert's answer
2022-06-15T07:03:35-0400

Given:

N=50; A=10cm2=103m2; B=0.75T; t=0.2s;N=50; \space A=10cm^{2}=10^{-3}m^{2}; \space B=0.75T; \space t=0.2s;

α=1800;\alpha=180^{0};

Solution:

Formula of induced EMF:

E=NΔϕΔt;E=-N\frac{\Delta\phi}{\Delta t}; Let's find Δϕ\Delta\phi - magnetic flux though the coil;

Δϕ==0αBδ(Acosα)=0πBδ(Acosα)=2BA;\Delta\phi==\int_0^αB\delta(Acosα)=\int_0^\pi B\delta(Acosα)=-2BA; here B and A constant;B\space and \space A \space constant;

E=NΔϕΔt=N2BAt=50×2×103m2×0.75T0.2s=0.375V;E=-N\frac{\Delta\phi}{\Delta t}=N\frac{2BA}{t}=50\times\frac{2\times10^{-3}m^{2}\times0.75T}{0.2s}=0.375V;

Answer:

E=0.375V.E=0.375V.


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