Question

An electric kettle is connected to a 120-V

outlet and has 11.5 A of current flowing

through it. What is the resistance in the

kettle?

Answer 1

Given:

$U=120V;$

$I=11.5A;$

Find:

$R$ - resistance of the kettle.

Solution:

Let's use Ohm's law fro part of circuit:

$I=\frac{U}{R}$ , $R=\frac{U}{I}=\frac{120V}{11.5A}=10.435\Omega.$

Answer:

$R=10.435\Omega.$