An electric kettle is connected to a 120-V
outlet and has 11.5 A of current flowing
through it. What is the resistance in the
kettle?
Given:
"U=120V;"
"I=11.5A;"
Find:
"R" - resistance of the kettle.
Solution:
Let's use Ohm's law fro part of circuit:
"I=\\frac{U}{R}" , "R=\\frac{U}{I}=\\frac{120V}{11.5A}=10.435\\Omega."
Answer:
"R=10.435\\Omega."
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