Question

An electromagnet exerts a force of 15 N and moves a soft iron armature through a distance of 12 mm in 50ms. Determine the power consumed

Answer 1

Given:

$F=15N;$

$d=12mm=0.012m;$

$t=50ms=0.05s.$

Find:

$P-?$

Solution:

Power consumed = (Work done by electromagnetic force)/(time);

$P=\frac{W}{t};$ $W=Fdcos\alpha$ ; here $\alpha=0;$ So,

$P=\frac{Fd}{t}=\frac{15N\times0.012m}{0.05s}=3.6W.$

Answer:

$P=3.6W.$