Question #311865

Two charges are located on the positive x-axis of a coordinate system. Charge š‘ž1 = 2 Ɨ 10āˆ’9š¶ is 2cm from the origin, and charge š‘ž2 = āˆ’3 Ɨ 10āˆ’9š¶ is 4cm from the origin. What is the total force exerted by these two charges on a charge š‘ž3 = 5 Ɨ 10āˆ’9š¶ located at the origin?


Expert's answer

Solution.

q1=2ā‹…10āˆ’9C;r1=0.02m;q_1=2\sdot10^{-9}C; r_1=0.02m;

q2=āˆ’3ā‹…10āˆ’9C;r2=0.04m;q_2=-3\sdot10^{-9}C; r_2=0.04m;

F13=kq1ā‹…q3r12;F_{13}=k \dfrac{q_1\sdot q_3}{r_1^2};

F13=9ā‹…1092ā‹…10āˆ’9ā‹…5ā‹…10āˆ’90.022=2.25ā‹…10āˆ’4N;F_{13}=9\sdot10^9\dfrac{2\sdot10^{-9}\sdot5\sdot10^{-9}}{0.02^2}=2.25\sdot10^{-4}N;

F23=kq2ā‹…q3r22;F_{23}=k\dfrac{q_2\sdot q_3}{r_2^2};

F23=9ā‹…1093ā‹…10āˆ’9ā‹…5ā‹…10āˆ’90.042=0.84ā‹…10āˆ’4N;F_{23}=9\sdot10^9\dfrac{3\sdot10^{-9}\sdot5\sdot10^{-9}}{0.04^2}=0.84\sdot10^{-4}N;

F=F13āˆ’F23=2.25ā‹…10āˆ’9āˆ’0.84ā‹…10āˆ’9=1.41ā‹…10āˆ’9N;F=F_{13}-F_{23}=2.25\sdot 10^{-9} - 0.84\sdot 10^{-9}=1.41\sdot10^{-9}N;

Answer: F=1.41ā‹…10āˆ’9N.F=1.41\sdot10^{-9}N.




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