Two charges are located on the positive x-axis of a coordinate system. Charge 𝑞1 = 2 × 10−9𝐶 is 2cm from the origin, and charge 𝑞2 = −3 × 10−9𝐶 is 4cm from the origin. What is the total force exerted by these two charges on a charge 𝑞3 = 5 × 10−9𝐶 located at the origin?
Solution.
q1=2⋅10−9C;r1=0.02m;q_1=2\sdot10^{-9}C; r_1=0.02m;q1=2⋅10−9C;r1=0.02m;
q2=−3⋅10−9C;r2=0.04m;q_2=-3\sdot10^{-9}C; r_2=0.04m;q2=−3⋅10−9C;r2=0.04m;
F13=kq1⋅q3r12;F_{13}=k \dfrac{q_1\sdot q_3}{r_1^2};F13=kr12q1⋅q3;
F13=9⋅1092⋅10−9⋅5⋅10−90.022=2.25⋅10−4N;F_{13}=9\sdot10^9\dfrac{2\sdot10^{-9}\sdot5\sdot10^{-9}}{0.02^2}=2.25\sdot10^{-4}N;F13=9⋅1090.0222⋅10−9⋅5⋅10−9=2.25⋅10−4N;
F23=kq2⋅q3r22;F_{23}=k\dfrac{q_2\sdot q_3}{r_2^2};F23=kr22q2⋅q3;
F23=9⋅1093⋅10−9⋅5⋅10−90.042=0.84⋅10−4N;F_{23}=9\sdot10^9\dfrac{3\sdot10^{-9}\sdot5\sdot10^{-9}}{0.04^2}=0.84\sdot10^{-4}N;F23=9⋅1090.0423⋅10−9⋅5⋅10−9=0.84⋅10−4N;
F=F13−F23=2.25⋅10−9−0.84⋅10−9=1.41⋅10−9N;F=F_{13}-F_{23}=2.25\sdot 10^{-9} - 0.84\sdot 10^{-9}=1.41\sdot10^{-9}N;F=F13−F23=2.25⋅10−9−0.84⋅10−9=1.41⋅10−9N;
Answer: F=1.41⋅10−9N.F=1.41\sdot10^{-9}N.F=1.41⋅10−9N.
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