A 670m long eureka wire has resistance of 250 ohms. What length of the same wire will have a resistance of 110 ohms?
Answer
Resistance is given by
R=ρlAR=\frac{\rho l}{A}R=Aρl
So in above case length of wire is given
l′=R′lR=110∗670250=294.8ml'=\frac{R'l}{R}\\=\frac{110*670}{250}\\=294.8ml′=RR′l=250110∗670=294.8m
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