plot a graph of voltage against current and find the slope, the slope you find from voltage to current is the resistance which is measured in ohm's.
the standard error on slope is given as 4(V2-V1)/6(12-11)
SAMPLE RESULTS
Current(A)0.10.20.30.4Voltage(V)1.22.43.64.8\begin{matrix} Current (A)& &0.1&0.2&0.3&0.4 \\ Voltage (V)& &1.2&2.4&3.6&4.8 \end{matrix}Current(A)Voltage(V)0.11.20.22.40.33.60.44.8
Slope of the graph
=ΔVΔI=\frac {\Delta V}{\Delta I}=ΔIΔV
=(4.2−1.0)(0.35−0.085)=12.075Ω=\frac{(4.2-1.0)}{(0.35-0.085)}=12.075\Omega=(0.35−0.085)(4.2−1.0)=12.075Ω
As per equation given
Standard error=4(V2−V1)6(I2−I1)=\frac{4(V_2-V_1)}{6(I_2-I_1)}=6(I2−I1)4(V2−V1)
=46×slope=\frac{4}{6}×slope=64×slope
=46×12.075=\frac{4}{6}×12.075=64×12.075
=8.05=8.05=8.05
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