Question #284324

Point charge q1 = -6.00 * 10-6 C is on the x-axis at x = -0.200 m. Point charge q2 is




on the x-axis at x = +0.400 m. Point charge q3 = +3.00 * 10-6 C is at the origin. What




is q2 (magnitude and sign) (a) if the net force on q3 is 6.00 N in the +x direction; (b)




if the net force on q3 is 6.00 N in the -x direction?

1
Expert's answer
2022-01-03T10:33:33-0500

Part (a)


F=k(q1q2)r2F=\frac{k(q_1q_2)}{r^2}


Fnet=F13+F23F_{net}=F_{13}+F_{23}


6=8.988×109[(6×106)(3×106)(0.2)2+(q2)(3×106)(0.4)2]6=8.988×10^9[\frac{(-6×10^{-6})(3×10^{-6})}{(-0.2)^2}+\frac{(q_2)(3×10^{-6})}{(0.4)^2}]


q2=+5.96×105Cq_2=+5.96×10^{-5}\>C


Part (b)


6=8.988×109[(6×106)(3×106)(0.2)2+(q2)(3×106)(0.4)2]-6=8.988×10^9[\frac{(-6×10^{-6})(3×10^{-6})}{(-0.2)^2}+\frac{(q_2)(3×10^{-6})}{(0.4)^2}]


q2=1.16×105Cq_2=-1.16×10^{-5}\>C



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