There are four equal-value resistors connected in series with a 5 V source. A current of 4.63 mA is measured. What is the value of each resistor?
I=E.m.f.ReffI=\frac{E.m.f.}{R_{eff}}I=ReffE.m.f.
Where I=4.63×10−3AI=4.63×10^{-3}AI=4.63×10−3A
E.m.f.=5VE.m.f.=5VE.m.f.=5V
Reff=R_{eff}=Reff= Effective resistance
=4R=4R=4R
Where R=R=R= The value of each resistor
4.63×10−3=54R4.63×10^{-3}=\frac{5}{4R}4.63×10−3=4R5
R=269.98ΩR=269.98\OmegaR=269.98Ω
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