The resistivity is 1.68 x 10^-8 Ωm. Calculate the length of a copper wire with diameter 4.00 mm that has a resistance of 5.00 Ω. Ans: 3.74 km.
Solution
Given data are as below
Resistance of wire (R) =5"\\Omega"
Radius of wire r=2.00mm
resistivity "\\rho=1.68 \\times 10^{-8}\u03a9m"
The resistance of any wire can written as
"R=\\frac{\\rho l}{A}"
Now then length of wire can be written as below formula
"l=\\frac{RA}{\\rho}"
Now putting all values
"l=\\frac{5\\times3.14\\times(2\\times10^{-3})^2}{1.68 \\times 10^{-8}}"
"l=\\frac{5\\times3.14\\times4\\times10^{-6}}{1.68 \\times 10^{-8}}"
"l=\\frac{20\\times3.14\\times10^{2}}{1.68 }"
"l=\\frac{62.8\\times10^{2}}{1.68}\\\\l=3.74Km"
So length of wire is 3.74Km
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