Answer to Question #253377 in Electric Circuits for Jayson

Question

A grindstone increases in angular speed from 4.00 rad/s to 12.00 rad/s in 4.00 s. (a) How many revolution does it turn during that time interval if the angular acceleration is constant? (b) What is the magnitude of its angular acceleration?

Answer 1

Answers: (a) $\theta =5.0929\text{ rev}$

Answers: (b) $\alpha=2\text{ rad/s}^2$