Question #253377
A grindstone increases in angular speed from 4.00 rad/s to 12.00 rad/s in 4.00 s. (a) How many revolution does it turn during that time interval if the angular acceleration is constant? (b) What is the magnitude of its angular acceleration?
1
Expert's answer
2021-10-20T10:39:18-0400


Answers: (a) θ=5.0929 rev\theta =5.0929\text{ rev}

Answers: (b) α=2 rad/s2\alpha=2\text{ rad/s}^2


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