Answer to Question #252877 in Electric Circuits for Pogi

Question #252877

Given a dc bias of 0.5mA and a bandwidth of 10kHz, calculate for the noise current


1
Expert's answer
2021-10-18T10:57:13-0400

Solution;

Noise current is given as follows;

In=2IqΔBI_n=\sqrt{2Iq\Delta B}

In Which;

I=DC current (A)

ΔB\Delta B =bandwidth (Hz)

q=charge of electron(c)

Given;

I=0.5mA=0.5×103AI=0.5mA=0.5×10^{-3}A

ΔB=10kHz=10×103Hz\Delta B=10kHz=10×10^3Hz

q=1.602×1019cq=1.602×10^{-19}c

By substitution;

InI_n =2×0.5×10×1.602×1019\sqrt{2×0.5×10×1.602×10^{-19}}

In=16.02×1019I_n=\sqrt{16.02×10^{-19}}

In=1.266×109AI_n=1.266×10^{-9}A

Answer;

Noise current,InI_n =1.266nA






Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment