Question #252503

Four forces are exerted on the eyebolt as shown. If the net effect on the bolt is a direct pull of 600 lb in the y-direction, determine the necessary values of T and ø


1
Expert's answer
2021-10-18T11:06:56-0400


the net effect:

R=240cosθ+Tcos30°+400cos60°=600R=240cos\theta+Tcos30\degree+400cos60\degree=600 lb


0=400cos30°+Tcos60°240sinθ3600=400cos30\degree+Tcos60\degree-240sin\theta-360


240cosθ+3T/2=400240cos\theta+\sqrt{3}T/2=400

T/2240sinθ=3602003T/2-240sin\theta=360-200\sqrt{3}


T/2=(400240cosθ)/3T/2=(400-240cos\theta)/\sqrt{3}

(400240cosθ)/3240sinθ=3602003(400-240cos\theta)/\sqrt{3}-240sin\theta=360-200\sqrt{3}


400240cosθ2403sinθ=3603600400-240cos\theta-240\sqrt3sin\theta=360\sqrt3-600

6cosθ+63sinθ=25936cos\theta+6\sqrt3sin\theta=25-9\sqrt3


36(1sin2θ)=6254503+243123sinθ(2593)+108sin2θ36(1-sin^2\theta)=625-450\sqrt3+243-12\sqrt3sin\theta(25-9\sqrt3)+108sin^2\theta

144sin2θ123sinθ(2593)+8324503=0144sin^2\theta-12\sqrt3sin\theta(25-9\sqrt3)+832-450\sqrt3=0


sinθ=195.6382654144(8324503)288=195.63826530284288=195.689.3288=0.3691sin\theta=\frac{195.6-\sqrt{38265-4\cdot144(832-450\sqrt3)}}{288}=\frac{195.6-\sqrt{38265-30284}}{288}=\frac{195.6- 89.3}{288}=0.3691


θ=21.66°\theta=21.66\degree


T=2(400240cos21.66°)/3=204T=2(400-240cos21.66\degree)/\sqrt3=204 lb


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