Answer to Question #251372 in Electric Circuits for Armando

Question

1. Three (3) AM broadcast stations are spaced at 18 kHz, beginning at 73 kHz. Each station is allowed to transmit modulating up to 6 kHz. Compute for the upper and lower sidebands of each station.

Answer 1

Initial frequency f_i = 73 kHz

Final frequency f_f = (73 + 18) kHz = 91 kHz

Let 

Station 1 be A, Station 2 be B and Station 3 be C

The f_USB of A = 73 kHz + f_m (6 kHz) = 79 kHz

The f_USB of B = 79 kHz + f_m (6 kHz) = 85 kHz

The f_USB of C = 85 kHz + f_m (6 kHz) = 91 kHz f_USB is the Frequency of the Upper Sidebands, while f_m is the modulating frequency at which each station is allowed to transmit.

Therefore, the frequency of the upper and lower sidebands of each station are given by:

1. A, f_LSB = 73 kHz and f_USB = 79 kHz;
2. B, f_LSB = 79 kHz and f_USB = 85 kHz;
3. C, f_LSB = 85 kHz and f_USB = 91 kHz.

f_LSB stands for Frequency of the Lower Sidebands.