A work of 30 joules is done in transferring 5 Millie coulombs of charge from a point B to point A in a electric field. The potential difference between B and A is?
W=30 J
Q=5 mC
W=QVV=WQW=QV\\V=\frac{W}{Q}W=QVV=QW
V=305×10−3V=6×103=6V=\frac{30}{5\times10^{-3}}V=6\times10^{3}=6V=5×10−330V=6×103=6 kV
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments