Question #243868

Assume Young's modulus for bone is 1.5 x 1010N/m². The bone breaks if stress greater than 1.5 x 108 N/m² is imposed on it. 1) What is the maximum force that can be exerted on the femur bone in the leg if it has a minimum effective diameter of 2.5 cm? 2) If this much force is applied compressively, by how much does the 25 cm long bone shorten?


1
Expert's answer
2021-09-30T14:29:41-0400

Pressure(P)=FA\frac{F}{A}

F=P×AF=P\times A

Area

A=π×2.52×1044A={\pi }\times{\frac{2.5^2\times10^{-4}}{4}}


F=1.5×108×π×2.52×1044=7.35×104NF=1.5\times10^{8}\times\pi \times\frac{2.5^2\times10^{-4}}{4}=7.35\times10^4N

We know that

Y=PLLY=\frac{P}{\frac{∆L}{L}}

L=P×LY∆L=\frac{P\times L}{Y}

Put value

L=1.5×108×0.251.5×1010=0.0025m=2.5mm∆L=\frac{1.5\times10^{8}\times 0.25}{1.5\times10^{10}}=0.0025m=2.5mm


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