A ball is thrown vertically upward and returns to its starting point 20 seconds later. Find its a) initial velocity; b) the maximum height it has reached.
Given:
"t=20\\:\\rm s"
The time of flight
"t=\\frac{2v_0}{g}"Hence,
a) initial velocity
"v_0=gt\/2=9.8*20\/2=98\\:\\rm m\/s"b) the maximum height that ball reached
"h_{\\max}=\\frac{v_0^2}{2g}=\\frac{98^2}{2*9.8}=490\\:\\rm m"
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