If three resistor are connected in series, what is the voltage drop in R1 if the value of R1= 12 ohm R2 = 20 ohm R3 = 5 ohm and the voltage source is Et = 24 volts
The total resistance is the sum of the individual resistances
"I=\\dfrac{E_t}{R_1+R_2+R_3}"
The voltage drop in "R_1" is
"U_1=\\dfrac{12\\ Ohm}{12\\ Ohm+20\\ Ohm+5\\ Ohm}\\cdot24 \\ V"
"=\\dfrac{288}{37}\\ V\\approx7.784\\ V"
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