What is the electric potential at the center of a square of side length 2.0 m with alternating + 3C, –2C, +3C, and –2C charges placed at its vertices
Answer
net charge
qnet=3+3−2−2=2Cq_{net}=3+3-2-2=2Cqnet=3+3−2−2=2C
Distance of all the charge from center
=22+222=1.4m\frac{\sqrt{2^2+2^2}}{2}=1.4m222+22=1.4m
So potential at center
V=kqr2=(9×109)(2)1.42=9.2×109VV=\frac{kq}{r^2}=\frac{(9\times10^9) (2) }{1.4^2}=9.2\times10^9VV=r2kq=1.42(9×109)(2)=9.2×109V
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