Question

Find the equivalent capacitance.

C1=3 µF, C2=5 µF, C3=2 µF, C4=2 µF, C5=4 µF, C6=6 µF

Answer 1

if the capacitors are in parallel, equivalent capacitance $=3+5+2+2+4+6=22$ µF

if the capacitors are in series, $1/C_E=1/3+1/5+1/2+1/2+1/4+1/6=39/20$

$C_E =20/39=0.5128µF$