Question

A 300v battery is connected across terminal t1 and t2 current will then begin to flow in the network in accordance with established laws of electricity flow.Amount of current flowing through each resistors in the circuit can accordingly the determined, strictly the circuit with 300v connected across t1 and t2 and then establish value of current flowing through resistors with lowest current.

Answer 1

We have given a $300V$ battery across two terminals $t_1 and t_2,$

Now let two resistances be $R_1 and R_2$

Consider that these resistances are connected in Series (to get lowest current)

Then, equivalent resistance is $R= R_1+R_2$

Then, current I flowing in the circuit is I=$\dfrac{300}{(R_1+R_2)}$

In order to get lowest current in the circuit resistance should be connected in Series.