Answer to Question #165002 in Electric Circuits for Zaeem

Question #165002

suppose you wish to store 1.0 kW.s in a parallel plate capicator when a potential difference of 10V is applied across its plates What must be the capacitance of your parallel plate capacitor


1
Expert's answer
2021-02-22T10:24:43-0500

Energy stored in a parallel plate capacitor(U)=12CV2(U)= \frac{1}{2}CV^2

Given, U=1.0 KW.s=1000 JU= 1.0\ KW.s=1000\ J

V=10 VV= 10\ V

Substituting these values in above equation,

1000=12C(10)2    C=20 F1000=\frac{1}{2}C(10)^2\implies C=20\ F


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