Answer to Question #162744 in Electric Circuits for Aarati

Question #162744

Implement the following combinational logic circuits 

a) Half-adder

b) Full-adder

c) Half- Subtractor

d) Full- Subtractor


1
Expert's answer
2021-02-11T12:07:03-0500

(a) Half adder:-

Truth table:


The sum of product(SOP) form for Sum and carry of half adder is given by,

Sum,S=Aˉ.B+A.Bˉcarry,C=A.B\text{Sum},S=\bar{A}.B+A.\bar{B}\\\text{carry},C=A.B

The logic circuit of half Adder is-



(b) Full Adder:-

Truth table:-



The sum of product(SOP) form for Sum and carry of full adder is given by,

Sum,S=Aˉ.Bˉ.C+A.Bˉ.C+A.Bˉ.Cˉ+A.B.Ccarry,C=A.B+Cin(A.Bˉ+Aˉ.B)\text{Sum},S=\bar{A}.\bar{B}.C+A.\bar{B}.C+A.\bar{B}.\bar{C}+A.B.C\\\text{carry},C=A.B+C_{in}(A.\bar{B}+\bar{A}.B)

The logic circuit of Full Adder is-



(C) Half Subtractor:-

Truth table:-


The sum of product(SOP) form for Difference and Borrow of half subtractor is given by,

Difference,D=Aˉ.B+A.BˉBorrow,Bi=Aˉ.B\text{Difference},D=\bar{A}.B+A.\bar{B}\\\text{Borrow},B_i=\bar{A}.B

The logic circuit of half Subtractor is-



(iv) Full Subtractor:-

Truth table-


The sum of product(SOP) form for Difference and Borrow of full subtractor is given by,

Difference,S=Aˉ.Bˉ.C+A.Bˉ.C+A.Bˉ.Cˉ+A.B.CBorrow,C=Aˉ.Bˉ.C+Aˉ.B.Cˉ+Aˉ.B.C+A.B.C\text{Difference},S=\bar{A}.\bar{B}.C+A.\bar{B}.C+A.\bar{B}.\bar{C}+A.B.C\\\text{Borrow},C=\bar{A}.\bar{B}.C+\bar{A}.B.\bar{C}+\bar{A}.B.C+A.B.C

The logic circuit of Full subtractor is-



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