Answer to Question #161110 in Electric Circuits for Tara

Question

two Identical resistors are connected in parallel across a battery their combined resistance is 12 ohms what is the resistance of each resistor

Answer 1

For parallel connection of resistors

$1 / R_ {sum} = 1 / R_1 + 1 / R_2 + ... + 1 / R_n$

where

$R_ {sum}$ - equivalent resistance

$R_n$ - resistance of n-th resistor

In the case of identical resistors, i.e. $R_1 = R_2 = ... = R_n$ , above formula may be simplified

$R_ {sum} = R / n$

Answer:

Resistance of each resistor

$R = n * R_{sum} = 2 * 12 = 24 \text { (Ohm)}$