two Identical resistors are connected in parallel across a battery their combined resistance is 12 ohms what is the resistance of each resistor
For parallel connection of resistors
"1 \/ R_ {sum} = 1 \/ R_1 + 1 \/ R_2 + ... + 1 \/ R_n"
where
"R_ {sum}" - equivalent resistance
"R_n" - resistance of n-th resistor
In the case of identical resistors, i.e. "R_1 = R_2 = ... = R_n" , above formula may be simplified
"R_ {sum} = R \/ n"
Answer:
Resistance of each resistor
"R = n * R_{sum} = 2 * 12 = 24 \\text { (Ohm)}"
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