Rh=1/resistivity
what is the relation between resistivity and hall coefficient may I get the relation with proof
Since hall coefficient is given by, "R_H =\\frac{ V t}{IB}"
where V is the voltage, I is current, t is the thickness and B is the magnetic field.
By Ohm's Law, "R = \\frac{V}{I} = \\frac{\\rho t}{A}" where "\\rho" is the resistivity
Then, "R_H =\\frac{ Rt}{B} = \\frac{\\rho t^2}{A B}"
where A is the area of cross section.
Comments
Leave a comment