Question #160429

Rh=1/resistivity

what is the relation between resistivity and hall coefficient may I get the relation with proof


Expert's answer

Since hall coefficient is given by, RH=VtIBR_H =\frac{ V t}{IB}

where V is the voltage, I is current, t is the thickness and B is the magnetic field.


By Ohm's Law, R=VI=ρtAR = \frac{V}{I} = \frac{\rho t}{A} where ρ\rho is the resistivity

Then, RH=RtB=ρt2ABR_H =\frac{ Rt}{B} = \frac{\rho t^2}{A B}

where A is the area of cross section.


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