The resistance of wire is
"R=\\frac{U} {I} =\\rho\\frac{l} {S},"
where U - the voltage at the ends of wire,
I - the current through the wire,
"\\rho" - resistivity of aluminium,
"l" - length of the wire,
S - cross-sectional area of the wire.
Length of the wire from equation above is
"l=\\frac{US} {\\rho I} = \\frac {3\\cdot 10^{-3}\\cdot 40 \\cdot 10^{-6} }{0.026\\cdot 0.5}=9.23\\cdot 10^{-6} \\space m"
Answer: "9.23\\cdot 10^{-6} \\space m"
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