The resistance of wire is
R=IU=ρSl,
where U - the voltage at the ends of wire,
I - the current through the wire,
ρ - resistivity of aluminium,
l - length of the wire,
S - cross-sectional area of the wire.
Length of the wire from equation above is
l=ρIUS=0.026⋅0.53⋅10−3⋅40⋅10−6=9.23⋅10−6 m
Answer: 9.23⋅10−6 m
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