Question #145491
14. The short-circuit current of the source is 5 A, the EMF of the source is 14 V. What is the highest
power in the external circuit can be obtained in this case?
1
Expert's answer
2020-11-23T05:27:18-0500

The maximum power is

P=U⋅I=14 V⋅5 A=70 WP = U \cdot I = 14\, V \cdot 5 \, A = 70 \, W.

Answer: 70 W.


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