Answer to Question #117452 in Electric Circuits for Ben

Question

Explain why RMS voltage value is more useful than the peak value. Show, by calculation, the peak voltage value if the effective voltage value in the UK is 230V.

Answer 1

The average time value of the power in the AC circuit is of practical importence $P=\frac{RI_{peac}^2}{2}$

The same power is provided by the DC current $I_{RMS}=\frac{I_{peac}}{\sqrt2}$

If $I_{RMS}=230V$ then $I_{peac}=I_{RMS}\sqrt2\approx324V$