Explanations & Calculations
1) Total voltage ; considering the 3"\\small \\Omega" resistor,
"\\qquad\\qquad\n\\begin{aligned}\n\\small V &= \\small 4A\\times3\\Omega\n\\end{aligned}"
; considering the top branch,
"\\qquad\\qquad\n\\begin{aligned}\n\\small V &= \\small i \\times 6\\Omega\n\\end{aligned}"
Now,
"\\qquad\\qquad\n\\begin{aligned}\n\\small i \\times 6\\Omega & = \\small 4 \\times 3\\\\\n\\small i &= \\small 2A\n\\end{aligned}"
Therefore, total current is "\\small i + 4A = \\bold{6A}"
2) Total voltage is "\\small V = 4A \\times 3\\Omega = \\bold{12V}"
3) Voltage across 2"\\small \\Omega" ,
"\\qquad\\qquad\n\\begin{aligned}\n\\small V_{2\\Omega} &= \\small iR\\\\\n&= \\small 2A \\times2\\Omega \\\\\n&= \\small \\bold{4V} \n\\end{aligned}"
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