V1=(20+40)⋅0.1=6VV_1=(20+40)\cdot0.1=6VV1=(20+40)⋅0.1=6V
V1=V2=6VV_1=V_2=6VV1=V2=6V , I2=6/20=0.3AI_2=6/20=0.3AI2=6/20=0.3A
So, we have
Itotal=I1+I2=0.3+0.1=0.4AI_{total}=I_1+I_2=0.3+0.1=0.4AItotal=I1+I2=0.3+0.1=0.4A Answer.
Rtotal=15+20(20+40)20+20+40=15+15=30ΩR_{total}=15+\frac{20(20+40)}{20+20+40}=15+15=30\OmegaRtotal=15+20+20+4020(20+40)=15+15=30Ω
Vtotal=30⋅0.4=12VV_{total}=30\cdot 0.4=12VVtotal=30⋅0.4=12V
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