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Question #96759
A trolley of mass 200 kg moves with a unifo s1 rm speed of 36 km/h on a frictionless track. speed A child of mass 20 kg runs on the trolley from one end to the other (10 m away) with a of 4 m relative to the trolley in a direction opposite to the its motion, and the trolley. i. What is th ii. e final speed of the trolley ? How much has the trolley moved from t jumps out of he time the child begins to run
Expert's answer
From the conservation of momentum:
(
m
+
M
)
V
=
m
(
v
−
u
)
+
M
v
(m+M)V=m(v-u)+Mv
(
m
+
M
)
V
=
m
(
v
−
u
)
+
M
v
(
20
+
200
)
36
3.6
=
20
(
v
−
4
)
+
200
v
(20+200)\frac{36}{3.6}=20(v-4)+200v
(
20
+
200
)
3.6
36
=
20
(
v
−
4
)
+
200
v
The final speed of the trolley:
v
=
10.4
m
s
v=10.4\frac{m}{s}
v
=
10.4
s
m
t
=
d
v
=
10
4
=
2.5
s
t=\frac{d}{v}=\frac{10}{4}=2.5\ s
t
=
v
d
=
4
10
=
2.5
s
Thus,
s
=
v
1
t
=
(
10.4
)
(
2.5
)
=
26
m
s=v_1t=(10.4)(2.5)=26\ m
s
=
v
1
t
=
(
10.4
)
(
2.5
)
=
26
m
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