The vertical part of the rope is shortened with acceleration "(3+4)m\/s^2" .
when the length of the vertical part of the rope decreases by "x" meters the height of the block C increases by "x\/2" meters, hence acceleration of the block C is "(3+4)\/2\\ m\/s^2=3.5\\ m\/s^2"
Answer: "3.5\\ m\/s^2."
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