Question #285244

Two sailors are at the tops of their ships’ masts in the open ocean. The mast of ship A is twice as high as that of ship B. How much farther can sailor A see than sailor B? a) no farther

b) a little more than 40% farther

c) twice as far

d) almost three times as far

e) four times as far


Please give me full explanation how to answer this question.

I want to know it for necessary.

Thank you so much.

1
Expert's answer
2022-01-07T09:29:57-0500

d=(R+h)2R2=2Rh+h2,d=\sqrt{(R+h)^2-R^2}=\sqrt{2Rh+h^2},

h<<R,h<<R,

d=2Rh,d=\sqrt{2Rh},

d2d2=h2h1=2h1h1=2.\frac{d_2}{d_2}=\sqrt{\frac{h_2}{h_1}}=\sqrt{\frac{2h_1}{h_1}}=\sqrt 2.

NO a) no farther

YES b) a little more than 40% farther

NO c) twice as far

NO d) almost three times as far

NO e) four times as far



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