Answer to Question #214223 in Classical Mechanics for tonny419

Question

Two vertically suspended wires are parallel to each other and are also 500 mm apart. The load P carried is W. The first wire is made out of copper and has a diameter of 4 mm. The second wire is made out of steel and has a diameter of 3 mm. The Young's Modulus of Elasticity is 100 GPa for copper and 200 GPa for steel. If the elongation is the same in both wires, calculate the position of W?

Answer 1

$E_1S_1l=E_2S_2(s-l),$

$S_i=\frac{\pi d_i^2}{4},$ $\implies$

$l=0.24~m.$