Two wooden cubes of side-length 'a' are placed one on another on a horizontal plane. 'M' and 'm' represent the masses of upper cube and lower cube respectively(M>m). The coefficient of dynamic friction between each surface is μ. The bottom wedge is given 'u' initial velocity and it is sufficient for that cube to slip away from the tower. Find the final horizontal displacement of the upper cube.
Given,
Mass of the blocks are and ,
Side length of the cube
Coefficient of dynamic friction between each surface
Initial velocity of the bottom wedge
Normal reaction on the lower block
Normal reaction on the upper block
So, As the systems are moving with velocity u, it means net force on the blocks are zero.
Now, substituting the values,
Let the acceleration of the upper block be A
So,
Now, substituting the values,
Hence,
Final velocity of the upper block
Hence,
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