Question

540 g of ice at 0°C is mixed with 540 g of water at 80°C, what is the final temperature of the mixture?

Answer 1

Answer

Specific heat capacity of water

$s_1=4.2KJ/kg°c$

Latent heat of fusion for ice

$L_f=336KJ/kg$

Total heat transfer of system will be zero.

So

Heat required to change the 0.54kg ice to 0°C water

$Q_1=0.54×336=181.44KJ$

Heat required for water to 80°C of water to 0°C of water

$Q_2=0.54×4.2×(80-0) =181.4KJ$

$Q_1=Q_2$

So final temperature of mixture will be 0°C