(specific heat capacity of copper = 380 J/kg°C)
1) 2.
Q=mc\Delta T=0.5\ kg\cdot4180\ Jkg^{-1}\ \!^{\circ}C^{-1}\cdot45^{\circ}C=94050\ J.3.
Q=mc\Delta T=0.95\ kg\cdot500\ Jkg^{-1}\ \!^{\circ}C^{-1}\cdot165^{\circ}C=78375\ J.1) 2.
Q=mc\Delta T=1.2\ kg\cdot4180\ Jkg^{-1}\ \!^{\circ}C^{-1}\cdot80^{\circ}C=401280\ J.3.
4. Since the cheaper kettle is not so well insulated, there will be the heat losses, therefore, it takes more time to heat the water.
1)
Q=mc\Delta T=0.03\ kg\cdot380\ Jkg^{-1}\ \!^{\circ}C^{-1}\cdot400^{\circ}C=4560\ J.
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