In a ball game a 70 kg player is running at 10 m/s when he is hit by the other player he bounces off in the opposite direction at 2 m/s. What is the players change in momentum?
before collision:\text{before collision:}before collision:
m=70;V1⃗=10;m = 70;\vec{V_1}=10;m=70;V1=10;
p⃗1=m∗V1⃗=10∗70=700\vec p_1=m*\vec{V_1} = 10*70 = 700p1=m∗V1=10∗70=700
after collision:\text{after collision:}after collision:
m=70;V2⃗=−2;m = 70;\vec{V_2}=-2;m=70;V2=−2;
p⃗2=m∗V2⃗=−2∗70=−140\vec p_2=m*\vec{V_2} = -2*70 = -140p2=m∗V2=−2∗70=−140
Δp=p⃗2−p⃗1=−140−700=−840kg∗ms\Delta p= \vec p_2-\vec p_1= -140-700 =-840kg*\frac{m}{s}Δp=p2−p1=−140−700=−840kg∗sm
Answer: Δp=−840kg∗ms\text{Answer: }\Delta p=-840kg*\frac{m}{s}Answer: Δp=−840kg∗sm
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