Calculate the rise in temperature produced.
Take the specific heat capacity of methylated spirit to be 2300 J/kg°C.
1.
m=Qc(t2−t1)=0.5 kg.m=\frac{Q}{c(t_2-t_1)}=0.5~kg.m=c(t2−t1)Q=0.5 kg.
2.
c=Qm(t2−t1)=105 Jkg⋅°C.c=\frac{Q}{m(t_2-t_1)}=105~\frac{J}{kg\cdot °C}.c=m(t2−t1)Q=105 kg⋅°CJ.
3.
Δt=Qmc=4°C.\Delta t=\frac{Q}{mc}=4°C.Δt=mcQ=4°C.
4.
Q=cm(t2−t1)=17625 J.Q=cm(t_2-t_1)=17625~J.Q=cm(t2−t1)=17625 J.
5.
t2=t1+Qcm=56°C.t_2=t_1+\frac{Q}{cm}=56°C.t2=t1+cmQ=56°C.
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