Question #180052

What is the potential energy of 800-kg elevator at the top of a 380 meter tall building?


1
Expert's answer
2021-04-15T07:18:24-0400

The potential energy is given by.


Ug=m    g  hU_{g}=m\;\;g\;h


Where.

h=380  mh=380\;\text{m} is the height above the ground.

g=9.81  m/s2g=9.81\;\text{m}/\text{s}^{2} is the acceleration of gravity.

m=800  Kgm=800\;\text{Kg} is the mass


Evaluating numerically.


Ug=m    g  hUg=800  Kg×9.81  m/s2×380  mUg=2,982,240  JU_{g}=m\;\;g\;h\\ U_{g}=800\;\text{Kg}\times 9.81\;\text{m}/\text{s}^{2}\times 380\;\text{m}\\ U_{g}=2,982,240\;\text{J} \\


Expressing in scientific notation with three significant figures.


Ug=2.98×106  JU_{g}=2.98\times 10^{6}\;\text{J}


The potential energy is Ug=2.98×106  J\displaystyle \color{red}{\boxed{U_{g}=2.98\times 10^{6}\;\text{J}}}


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS