An object is attracted towards the origin with a force given by F = 6x^3 . a) What is the force at (1,0)? b) what is the work done by the when the object moves from (1,0) to (2,0)?
a)
F=6⋅13=6 N,F=6\cdot 1^3=6~N,F=6⋅13=6 N,
b)
A=∫121+F′2(x)dx=∫121+324x4dx≈42 J.A=\int _1^2\sqrt{1+F'^2(x)}dx=\int_1^2\sqrt{1+324x^4}dx\approx 42~J.A=∫121+F′2(x)dx=∫121+324x4dx≈42 J.
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