Question #172473

Starting from rest a car attains an acceleration of 2 m/s-2


Find the time and velocity at this position. (in km/hr)


1
Expert's answer
2021-03-21T11:37:12-0400

Unfortunately, from the condition of the question we don't know the position of the car. Let's assume that the car attains an acceleration of 2 m/s-2 at position d=10 md=10\ m. Then, we can find the time that the car takes to accelerate from the formula:


d=v0t+12at2,d=v_0t+\dfrac{1}{2}at^2,d=12at2,d=\dfrac{1}{2}at^2,t=2da=210 m2 ms2=3.16 s.t=\sqrt{\dfrac{2d}{a}}=\sqrt{\dfrac{2\cdot10\ m}{2\ \dfrac{m}{s^2}}}=3.16\ s.

Finally, we can find the velocity at this position:


v=v0+at,v=v_0+at,v=0+2 ms23.16 s=6.32 ms(1 km1000 m)(3600 s1 h)=22.75 kmh.v=0+2\ \dfrac{m}{s^2}\cdot3.16\ s=6.32\ \dfrac{m}{s}\cdot(\dfrac{1\ km}{1000\ m})\cdot(\dfrac{3600\ s}{1\ h})=22.75\ \dfrac{km}{h}.

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